You visited us 1 times! Enjoying our articles? Unlock Full Access!

Vector Addition

Forces F⃗1 an...

Question

Forces $_{1}$ and $_{2}$ act on a point mass in two mutually perpendicular directions. The resultant force on the point mass will be

F_{1} + F_{2}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

F_{1} - F_{2}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

\sqrt{F_{1}^{2} + F_{2}^{2}}

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

F_{1}^{2} + F_{2}^{2}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is C $\sqrt{F_{1}^{2} + F_{2}^{2}}$

$F = \sqrt{F_{1}^{2} + F_{2}^{2} + 2 F_{1} F_{2} c o s 90^{\circ}} = \sqrt{F_{1}^{2} + F_{2}^{2}}$

Suggest Corrections

Similar questions

{\to F}_{1} = 500 N

{\to F}_{2} = 250 N

{\to F}_{2} - {\to F}_{1}

3 N

4 N

12 N

7 k g

{\to F}_{1} = 20^i + 30^j

{\to F}_{2} = 8^i - 5^j

m s^{- 2}

_{1} = 3^i + 4^j

{\to F}_{1} = 3^j + 4^k

Join BYJU'S Learning Program