Forces with magnitudes proportional to AB,BC and 2CA act along the sides of a triangle ABC in order. Their resultant is represented in magnitude and direction by:
A
CA
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B
AC
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C
BC
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D
CB
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Solution
The correct option is ACA →AB+→BC+→CA=→0 since →AB+→BC=→AC and →CA=−→AC ∴→AB+→BC+2→CA=(→AB+→BC+→CA)+→CA=→0+→CA=→CA