Graphs of Quadratic Equation for Different Values of D when a<0
Forfx=ax2+bx+...
Question
Forf(x)=ax2+bx+c,a≠0, the conditions for which the graph is a downward opening parabola and f(x)=0 have a unique root with multiplicity 2 is
A
a<0,D<0
No worries! We‘ve got your back. Try BYJU‘S free classes today!
B
a<0,D=0
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
C
a>0,D=0
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
a>0,D<0
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution
The correct option is Ba<0,D=0 Given: f(x)=ax2+bx+c,a≠0
For graph to be a downward opening parabola we must have a<0
Also, the equation has one root with a multiplicity 2. This means the equation has identical real roots which occurs when discriminant D=0.