Question

Form a quadratic polynomial whose zeroes are the H.C.F. and L.C.M. of $6$ and $9$.

Answer 1

H.C.F of $6$ and $9=3$

L.C.M of $6$ and $9=18$

$\therefore$ zeroes $=3,18$

Quadratic polynomial $=(x-3)(x-18)$

$=x(x-18)-3(x-18)$

$=x^2-18x-3x+54$

$=x^2-21x+54$

$\therefore$ Quadratic polynomial $:x^2-21x+54$.