Question

Form algebraic equations for the following statements and solve.

$10$ less than $4$ times a number is $26$. Find the number.

Answer 1

Step-1: To form the algebraic equation:

Let the number be $x$.

$4$ times a number is $4x$.

Now, taking $10$ less than $4$ times a number.

The expression formed is $4x-10$.

As per the given condition,

$4x-10=26$

Thus, $4x-10=26$ is the required algebraic equation.

Step-2: To find the solution of $4x-10=26$:

$4x-10=26$

Transposing $10$ to the R.H.S,

$\Rightarrow$$4x=26+10$

$\Rightarrow$$4x=36$

$\Rightarrow$ $x=\frac{36}{4}$

$\Rightarrow$ $x=9$

Therefore, the required number is $9$.