wiz-icon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

Form quadratic equation x5ax1=xbbx1

Open in App
Solution

We have,

x5ax1=xbbx1

(x5)(bx1)=(ax1)(xb)

bx25bxx+5=ax2xabx+b

bx25bx+5=ax2abx+b

bx2ax25bx+abx+5b=0

x2(ba)b(5bab)+(5b)=0

Hence, this is the answer.


flag
Suggest Corrections
thumbs-up
0
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Nature and Location of Roots
MATHEMATICS
Watch in App
Join BYJU'S Learning Program
CrossIcon