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Question

Form the differential equation corresponding to y=Acos3x+B sin3x, where A and B are parameters.

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Solution

y=Acos3x+Bsin3x ....(1)
Differentiate
y=3Asin3x+3Bcos3x
again differentiate,
y′′=9Acos3x9Bsin3x
y′′=9(Acos3x+Bsin3x)=9y, using (1)
y′′+9y=0

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