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Question

Form the differential equation of the family of circles in the first quadrant which touch the coordinate axes.

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Solution

The equation of a circle in the first quadrant with centre (a, a) and radius (a) which touches the coordinate axes is:

Differentiating equation (1) with respect to x, we get:

Substituting the value of a in equation (1), we get:

Hence, the required differential equation of the family of circles is


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