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Question

Form the differential equation of the family of hyperbolas having foci on the x-axis and center at the origin.


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Solution

Step 1: Define the equation of hyperbola and differentiate it

The equation of hyperbola having foci on the x-axis and center at the origin is,

x2a2-y2b2=1 …(i)

Where, a and b are parameters.

Differentiating equation (i) with respect to x,

2xa2-2yb2dydx=0 [ddxxn=nxn-1,ddxC=0]

2xa2=2yb2dydx

xa2=yb2dydx

b2a2x=ydydx …(ii)

b2a2=yxdydx …(iii)

Differentiating equation (ii) with respect to x.

b2a2×1=dydxddxy+yddxdydx

b2a2=dydxdydx+yd2ydx2

b2a2=dydx2+yd2ydx2 …(iv)

Step 2 : Compare the values of b2a2

Using equation (iii) and equation (iv),

yxdydx=dydx2+yd2ydx2

Or, yxy1=y12+yy2 [dydx=y1,d2ydx2=y2]

yxy1=y12+yy2

yy1=xy12+yy2

0=xy12+yy2-yy1

Or, xy12+yy2-yy1=0

which is the required differential equation.

Hence, xy12+yy2-yy1=0 is the differential equation of the family of hyperbolas having foci on the x-axis and center at the origin


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