CameraIcon
CameraIcon
SearchIcon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

Form the equation whose roots are 0,±a,cb.

Open in App
Solution

The roots of the required equation are 0,±a,cb
So the equation should be divisible by x,(xa),(x+a),(xcb)
So the required equation is x(xa)(x+a)(xcb)=0
(x2cbx)(x2a2)=0
x4cbx3a2x2+ca2bx=0
bx4cx3a2bx2+a2cx=0

flag
Suggest Corrections
thumbs-up
0
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Conjugate of a Complex Number
MATHEMATICS
Watch in App
Join BYJU'S Learning Program
CrossIcon