Question

Form the frequency distribution table from the following data:

Marks (out of $90$) - Number of candidates

More than or equal to $80$ - $4$

More than or equal to $70$ - $6$

More than or equal to $60$ - $11$

More than or equal to $50$ - $17$

More than or equal to $40$ - $23$

More than or equal to $30$ - $27$

More than or equal to $20$ - $30$

More than or equal to $10$ - $32$

More than or equal to $0$ - $34$

Answer 1

Form the distribution table:

The given data is as follows,

Marks (out of $90$) - Number of candidates

More than or equal to $80$ - $4$

More than or equal to $70$ - $6$

More than or equal to $60$ - $11$

More than or equal to $50$ - $17$

More than or equal to $40$ - $23$

More than or equal to $30$ - $27$

More than or equal to $20$ - $30$

More than or equal to $10$ - $32$

More than or equal to $0$ - $34$

First, form class intervals using the marks obtained by the candidates as,

$0-10,10-20,20-30,30-40,40-50,50-60,60-70,70-80$ and $80-90$ (since maximum marks is $90$).

Also, since the number of candidates scoring more than $0$ is $34$.

So, total candidates $=34$

Then, the frequency distribution table can be drawn as follows,

Class Interval (Marks)	Number of Candidates (Frequency)
$0-10$	$34-32=2$
$10-20$	$32-30=2$
$20-30$	$30-27=3$
$30-40$	$27-23=4$
$40-50$	$23-17=6$
$50-60$	$17-11=6$
$60-70$	$11-6=5$
$70-80$	$6-4=2$
$80-90$	$4$

Here, the sum of frequencies is $34$, i.e., the total number of candidates.

Hence, the required frequency table of the given data is

Class Interval (Marks)	Number of Candidates (Frequency)
$0-10$	$34-32=2$
$10-20$	$32-30=2$
$20-30$	$30-27=3$
$30-40$	$27-23=4$
$40-50$	$23-17=6$
$50-60$	$17-11=6$
$60-70$	$11-6=5$
$70-80$	$6-4=2$
$80-90$	$4$