Form the given monomials $33 a b, 12 a, 18 b^{2}$ find the H.C.F.

3 a b

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3 b^{2}

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3 b

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3

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Solution

The correct option is D $3$
$33 a b, 12 a, 18 b^{2}$
$33 = 3 \times 11 \times a b$
$12 a = 3 \times 4 \times a$
$18 b^{2} = 3 \times 6 \times b^{2}$
So, the common factor is $3$ .
Therefore, H.C.F. of the monomials $33 a b, 12 a, 18 b^{2}$ is $3$ .

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