Form the greatest and the smallest 3-digit numbers using any three different digits with the condition that digit 6 is always at the unit (one’s) place.

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Solution

Step1: Finding the smallest and the largest 3-digit numbers

Given condition,

The condition that digit 6 is always at the unit (one’s) place.

We know that 9 > 8

So, the greatest 3-digit number = 986

For the smallest 3-digit number 1 will be the leftmost digit because if there will be 0 in leftmost then it will be a 2-digit number only.

Thus, the smallest 3-digit number = 106

Hence, the required greatest number is 986 and the required smallest number is 106.

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a.) Largest 4-digit number using any four different digits with digit 5 always at the tens place	i.)1032
b.) Largest 4-digit number formed from the digits 5, 0, and 7 by using any one digit twice	ii.)3399
c.) Smallest 4-digit number using any four different digits with digit 2 always at the ones place	iii.)7750
d.) Smallest 4-digit number formed using the digits 3 and 9 equal number of times	iv.)9857

\begin{matrix} a.) Largest 4-digit number using any four different digits with digit 5 always at the tens place & i .) 1032 b.) Largest 4-digit number formed from the digits 5, 0, and 7 by using any one digit twice & i i .) 3399 c.) Smallest 4-digit number using any four different digits with digit 2 always at the ones place & i i i .) 7750 d.) Smallest 4-digit number formed using the digits 3 and 9 equal number of times & i v .) 9857 \end{matrix}

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