Question

Form the pair of linear equations for the following problem and find their solution by the substitution method.
The difference between two numbers is $26$ and one number is three times the other find them.

Answer 1

Let the two numbers be x and y

$x-y=26$ …………$\left(1\right)$

$x=3y$ ………..$\left(2\right)$

Substituting $\left(2\right)$ in $\left(1\right)$, we get

$3y-y=26$

$2y=26$

$y=13$

$x=3y$

$x=3\times 13=39$

$\therefore$ The two numbers are $39$ and $13$.