Form the quadratic equation if its roots are:
$- 3$ and $- 11$

x^{2} - 14 x + 33 = 0

No worries! We‘ve got your back. Try BYJU‘S free classes today!

x^{2} + 14 x + 33 = 0

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

x^{2} + 14 x - 33 = 0

No worries! We‘ve got your back. Try BYJU‘S free classes today!

x^{2} + 14 x + 18 = 0

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is A $x^{2} + 14 x + 33 = 0$
The equation whose roots are -3 and -11 are
$(x + 3) (x + 11) = 0$
$x^{2} + 11 x + 3 x + 33 = 0$
$x^{2} + 14 x + 33 = 0$

Suggest Corrections

Similar questions

x^{2} + 14 x + 33

x^{2} - 14 x + 38 = 0

x^{2} - 11 x + a = 0

x^{2} - 14 x + 2 a = 0

a =

x^{2} + 14 x + 13 = 0 = 0

f (x) = (\begin{matrix} x^{2} - 1, if 0 < x < 2 2 x + 3, if 2 \leq x < 3 \end{matrix}

lim x \to 2^{-} f (x) and lim x \to 2^{+} f (x)

Join BYJU'S Learning Program