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B
2x2−x−15=0
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C
x2+x−45=0
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D
x2−x−45=0
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Solution
The correct option is A2x2+x−15=0 The roots of the equation are −3 and 52 Thus the quadratic equation is (x+3)(x−52)=0 (x+3)(2x−5)=0 2x2+6x−5x−15=0 ∴2x2+x−15=0