Form the quadratic equation whose roots are:
$- 5$ and $9$

x^{2} + 4 x - 45 = 0

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x^{2} - 14 x - 45 = 0

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x^{2} + 14 x - 45 = 0

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x^{2} - 4 x - 45 = 0

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Solution

The correct option is D $x^{2} - 4 x - 45 = 0$
The roots of the equation are $- 5$ and $9$ . Hence, the equation will be:
$(x + 5) (x - 9) = 0$
$x (x - 9) + 5 (x - 9) = 0$
$x^{2} - 9 x + 5 x - 45 = 0$
$∴ x^{2} - 4 x - 45 = 0$

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