Question

Form the quadratic equation whose roots are:

$\frac{3}{4}$ and $\frac{-3}{4}$

• A. $16x^2+9=0$
• B. $16x^2-9=0$
• C. $4x^2-9=0$
• D. $4x^2+9=0$

Answer 1

The correct option is B $16x^2-9=0$

The roots are $\frac{3}{4}$ and $\frac{-3}{4}$

Thus, the equation is $(x-\frac{3}{4}\left)\right(x+\frac{3}{4})=0$

By using formula : $a^2-b^2=(a+b)(a-b)$

$\therefore x^2-(\frac{3}{4}{)}^2=0$

$\therefore 16x^2-9=0$