Question

Form the table representing the function $f:R\to R\{6y=2-27x;x,y\in R\}$ and identify the correct ordered pair.

• A. $x$ $y$

  $-1$	$\frac{29}{6}$
  $0$	$\frac{2}{6}$
  $1$	$-\frac{25}{6}$
  $2$	$-\frac{26}{3}$

• B. $x$ $y$

  $-3$	$\frac{83}{6}$
  $0$	$\frac{2}{6}$
  $1$	$\frac{25}{6}$
  $3$	$-\frac{79}{6}$

• C. Ordered pairs: $(\frac{29}{6},-1),(\frac{2}{6},0),(-\frac{25}{6},1),(-\frac{26}{3},2)$
• D. Ordered pairs: $(-1,\frac{29}{6}),(0,\frac{2}{6}),(1,-\frac{25}{6}),(2,-\frac{26}{3})$

Answer 1

Answer: (A), (D)

Ordered pairs: $(-1,\frac{29}{6}),(0,\frac{2}{6}),(1,-\frac{25}{6}),(2,-\frac{26}{3})$

The given function is $6y=2-27x.$
Let's form the table of the function for few values of $x.$
$x$ $y$

$-1$	$y=\frac{2-27(-1)}{6}=\frac{29}{6}$
$0$	$y=\frac{2}{6}$
$1$	$y=\frac{2-27\left(1\right)}{6}=-\frac{25}{6}$
$2$	$y=\frac{2-27\left(2\right)}{6}=-\frac{26}{3}$

The corresponding ordered pairs are: $(-1,\frac{29}{6}),(0,\frac{2}{6}),(1,-\frac{25}{6}),(2,-\frac{26}{3})$