Form the top of a cliff 92 m high, the angle of depression of a buoy is $20^{0}$ . Calculate, to the nearest metre, the distance of the buoy from the foot of the cliff.

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Solution

distance of the boy from the cliff = $\frac{92}{tan 20^{o}}$
$= 252.77 m$

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From the top of a cliff 92 m high, the angle of depression of a buoy is 20^o. Calculate to the nearest metre, the distance of the buoy from the foot of the cliff.

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Form the top of a cliff 92 m high, the angle of depression of a buoy is 200. Calculate, to the nearest metre, the distance of the buoy from the foot of the cliff.

distance of the boy from the cliff = 92tan20o =252.77m

Form the top of a cliff 92 m high, the angle of depression of a buoy is $20^{0}$ . Calculate, to the nearest metre, the distance of the buoy from the foot of the cliff.

distance of the boy from the cliff = $\frac{92}{tan 20^{o}}$
$= 252.77 m$