Formation of alkane by the action of zinc on alkyl halide is called:

Wurtz reaction.

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Kolbe's reaction.

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Ulmann's reaction.

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Frankland reaction.

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Solution

The correct option is D Frankland reaction.
(i) wurtz reaction

$2 R X + 2 N a E t h e r - -- \to R - R a l k a n e$

(ii) Kolbe's reaction

$R C O O N a + H_{2} O E l e c t r o l y s i s - ------ \to R - R a l k a n e$

(iii) Ulmann's reaction

$2 C_{6} H_{5} I + 2 C_{u} ⟶ C_{6} H_{5} - C_{6} H_{5} b i p h e n y l$

(iv) Frankland reaction

$2 R X + Z n a l k y l h a l i d e ⟶ R - R a l k a n e$

Hence,option D is correct.

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