Formation of NaCl involves:

loss of protons

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sharing of electrons

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loss of electrons

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gain of electrons

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Solution

The correct option is D gain of electrons
NaCl has ionic bonding. Sodium (Na) atom loses an electron to become positively charged (Na+), and chlorine atom (Cl) gains an electron to become negatively charged (Cl-). The oppositely charged ions then come together to form sodium chloride.

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$A g N O_{3 (a q)} + N a C l_{(a q)} \to A g C l_{(s)} + N a N O_{3 (a q)}$ .
Above reaction involves formation of precipitate.

N a (s) S - ------------ \to Energy of subtimation N a (g)

N a (g) I - ---------- \to Ionisation potenital N a^{+} (g) + e^{-}

C l_{2} (g) D - -------------- \to Bond dissociation energy 2 C l (g)

C l (g) + e^{-} E - --------- \to Electron - affinity C l^{-} (g)

C l^{-} (g) + N a^{+} (g) U - ------- \to Lattice energy N a C l (s)

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