Formula for sodium carbonate is:

True

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False

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{N a}_{2} C O_{3}

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{N a}_{3} C O_{2}

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Solution

The correct option is C ${N a}_{2} C O_{3}$
For sodium carbonate we have Na and $C O_{3}$ as its constituent molecules.

Symbol: Na $C O_{3}$

Valency: +1 -2

By criss crossing the valencies we get the chemical formulae of sodium carbonate as ${N a}_{2} C O_{3}$ .

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The correct order of the O - O bond length in $O_{2}$ , $H_{2} O_{2}$ and $O_{3}$ is

3 M

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{N a}_{2} S_{2} O_{3}

{N a}_{2} S_{2} O_{3}

{N a}^{+}

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