Formula of magnetite is -

F e_{2} O_{3}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

F e S_{2}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

F e C O_{3}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

F e_{3} O_{4}

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

Open in App

Solution

The correct option is D $F e_{3} O_{4}$
$F e_{2} O_{3}$ is Hematite
$F e S_{2}$ is Iron Pyrite
$F e C O_{3}$ is Siderite
$F e_{3} O_{4}$ is Magnetite

Hence, Option "D" is the correct answer

Suggest Corrections

Similar questions

Match the following iron ores with their formulae.

$\begin{matrix} Name of ore & Formula i) Magnetite & a) F e_{2} O_{3} ii) Haematite & b) F e S_{2} iii) Spathic iron ore & c) F e C O_{3} iv) Iron pyrite & d) F e_{3} O_{4} \end{matrix}$

Q. Equivalent weight of

F e S_{2}

in the half reaction,

F e S_{2} \to F e_{2} O_{3} + S O_{2}

is:

Q. Consider the reaction:

F e_{2} O_{3} ⟶ F e_{3} O_{4}

n

-factor for

F e_{3} O_{4}

is :

Q. Equivalent weight of

F e S_{2}

[mol.wt = M] in the following reaction is?

F e S_{2} + O_{2} \to F e_{2} O_{3} + S O_{2}

Q. When

F e S_{2}

is burnt in air, it converts to

F e_{2} O_{3}

as,

F e S_{2} (s) + O_{2} (g) \to F e_{2} O_{3} (s) + S O_{2} (g)

, the change in percentage by weight of iron in the process is:

(Atomic mass of Fe = 56 u)

Join BYJU'S Learning Program

Formula of magnetite is -

The correct option is D Fe3O4Fe2O3 is HematiteFeS2 is Iron PyriteFeCO3 is SideriteFe3O4 is MagnetiteHence, Option "D" is the correct answer

The correct option is D $F e_{3} O_{4}$
$F e_{2} O_{3}$ is Hematite
$F e S_{2}$ is Iron Pyrite
$F e C O_{3}$ is Siderite
$F e_{3} O_{4}$ is Magnetite

Hence, Option "D" is the correct answer