Formula to find the area of a semicircle with radius $r$ is:

π r^{2}

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2 π r^{2}

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\frac{1}{2} π r

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\frac{1}{2} π r^{2}

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Solution

The correct option is D $\frac{1}{2} π r^{2}$
Given radius $= r$
Perimeter of a circle $= π r^{2}$
Perimeter of semi circle $= \frac{π r^{2}}{2}$

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Similar questions

Tick the correct answer in the following:

Area of a sector of angle p (in degrees) of a circle with radius R is

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Q. If R is the outer radius of a hollow cylinder, r its inner radius, and h its height, then its volume (in cu. units) is:

Tick the correct answer in the following.
Area of a sector of angle $p^{\circ}$ of a circle with radius $R$ is:
1. $\frac{p^{\circ}}{180^{\circ}} \times 2 π R$
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Q. TSA of hemisphere of radius 'r' is 2πr

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Area of a sector with angle p (in degrees) of a circle with radius r is

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Formula to find the area of a semicircle with radius r is:

The correct option is D 12πr2Given radius=rPerimeter of a circle =πr2Perimeter of semi circle =πr22

Formula to find the area of a semicircle with radius $r$ is:

The correct option is D $\frac{1}{2} π r^{2}$
Given radius $= r$
Perimeter of a circle $= π r^{2}$
Perimeter of semi circle $= \frac{π r^{2}}{2}$