Question

Four alphabets $E,K,S$ and $V$, one in each, were purchased from a plastic warehouse. How many ordered pairs of alphabets, to be used as initials can be formed from them?

Answer 1

$E,K,S$ and $V$ one in each, were purchased from a plastic warehouse.

The required number of ordered pairs of alphabets, to be used as initials, can be formed $=P(4,2)=\frac{4!}{2!}=4\times 3=12$.