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Question
Four atoms are arbitrarily labelled D,E,F and G. Their electronegativities are as follows D=3.8, E=3.3, F=2.8 and G=1.3. If the atoms of these elements form the molecules DE,DG,EG, and DF which molecule has the lowest covalent bond character?
Four atoms are arbitrarily labelled D,E,F and G. Their electronegativities are as follows D=3.8, E=3.3, F=2.8 and G=1.3. If the atoms of these elements form the molecules DE,DG,EG, and DF which molecule has the lowest covalent bond character?
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Solution
The correct option is B DG
Smaller the (EN) difference, larger the covalent nature.
DG<EG<DF<DE−−−−−−−−−−−−−−−−−−−−→increasing covalent bond character
ENDG=3.8−1.3=2.5
ENDF=3.8−2.8=1.0
ENDE=3.8−3.3=0.5
ENEG=3.3−1.3=2.0
Smaller the (EN) difference, larger the covalent nature.
DG<EG<DF<DE−−−−−−−−−−−−−−−−−−−−→increasing covalent bond character
ENDG=3.8−1.3=2.5
ENDF=3.8−2.8=1.0
ENDE=3.8−3.3=0.5
ENEG=3.3−1.3=2.0
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