Four bells toll at an interval of $8, 12, 15$ and $18$ seconds respectively. All the four being to toll together. How many times will they toll together in one hour excluding the one at the start?

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Solution

Given,
Four bells toll after an interval of 8,9,12,15 minutes, respectively.
To find out the time when they will toll together next, we will calculate the L.C.M of the given numbers.
LCM of $8, 12, 15, 18 = 360.$
No. of seconds in one hour $= 3600$
So the bells will toll together $=$ $\frac{3600}{360}$ $= 10$ times
Hence, all the four bells being to toll together excluding one at the start is 10 times.

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Four bells toll at an interval of 8,12,15 and 18 seconds respectively. All the four being to toll together. How many times will they toll together in one hour excluding the one at the start?

Four bells toll at an interval of $8, 12, 15$ and $18$ seconds respectively. All the four being to toll together. How many times will they toll together in one hour excluding the one at the start?