Question

Four bodies of masses $2,3,5$ and $8kg$ are placed at the four corners of a square of side $2m$ The position of $CM$ will be :

Answer 1

The coordinate of the centre of mass is given as,

$x_{CM}=\frac{2\times 0+3\times 2+8\times 0+5\times 2}{2+3+5+8}$

$x_{CM}=\frac{8}{9}m$

$y_{CM}=\frac{2\times 0+3\times 0+8\times 2+5\times 2}{2+3+5+8}$

$y_{CM}=\frac{13}{9}m$

Thus, the position of centre of mass is $\left(\frac{8}{9},\frac{13}{9}\right)$.