Question

Four bolts P, Q, R, and S of equal diameter are used for a bracket subjected to a load of 130 kN as shown in the figure.


The force in bolt P is ______.

Answer 1

Direct shear in bolt P,

$F_1=\frac{130}{4}=32.5kN$

Shear due to twisting moment

$=\frac{130\times 200\times \sqrt{{120}^2+{150}^2}}{4(\sqrt{{120}^2+{50}^2}{)}^2}$

$F_2$ = 50 KN

$\theta =ta{n}^{-1}\left(\frac{120}{50}\right)={67.38}^o$



Resultant force in bolt P

$=\sqrt{F_1^2+F_2^2+2F_1{F}_{2}cos\theta }$

$=\sqrt{{32.5}^2+{50}^2+2\times 32.5\times 50cos{67.38}^o}$

= 69.32 kN