Question

Four boys are running in a race:

Manny, Nick, Oliver, and Pete.

Pete is ahead of Nick by $11meters.$

Oliver is ahead of Manny by $10meters.$

Oliver is ahead of Pete by $5meters.$

How far is the runner in first place ahead of the runner in last place?

Answer 1

Finding how far is the runner in first place ahead of the runner in last place:

Given that,
Oliver is ahead of Manny by $10meters$ , Oliver is ahead of Pete by $5meters$, Pete is ahead of Nick by $11meters.$
That means $\mathrm{O}>\mathrm{P}>\mathrm{M}>\mathrm{N}$, where $\mathrm{O}$ is Oliver , $\mathrm{P}$ is Pete , $\mathrm{M}$ is Manny and $\mathrm{N}$ is Nick
$$\begin{gathered} \Rightarrow \mathrm{O}\stackrel{5\mathrm{m}}{\to }\mathrm{P}\stackrel{11\mathrm{m}}{\to }\mathrm{N} \\ \Rightarrow \mathrm{O}\stackrel{10\mathrm{m}}{\to }\mathrm{M} \end{gathered}$$
The distance between First and last place is $16\mathrm{m}$

Hence, the required answer is $16\mathrm{m}$