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Question

Four bulbs B1,B2,B3 and B4 of 100 W each are connected to 220 V main as shown in the figure. The reading in an ideal ammeter will be :
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A
0.45 A
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B
0.90 A
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C
1.35 A
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D
1.80 A
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Solution

The correct option is C 1.35 A
Answer is C

Current through each bulb =100/220=5/11A
The ammeter reads only the Current which passing through
B2B3B4

Therefore current through ideal ammeter = 3×5/11=1.35A .

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