Question

Four cards are drawn at random from a pack of 52 cards. Find the probability of getting all the four cards of different numbers.

• A. $\frac{141}{4165}$
• B. $\frac{117}{833}$
• C. $\frac{264}{4165}$
• D. None of these

Answer 1

The correct option is C $\frac{264}{4165}$

$n\left(E\right){=}^{13}{C}_1{\times }^{12}{C}_1{\times }^{11}{C}_1{\times }^{10}{C}_1=13\times 12\times 11\times 10n\left(S\right){=}^{52}{C}_4=270725\therefore P\left(E\right)=\frac{13\times 12\times 1110}{270725}=\frac{264}{4165}$