Question

Four cells each of emf $2\text{V}$ and internal resistance $1\Omega$ are connected in parallel with an external resistance of $6\Omega$. The current in the external resistance is

Answer 1

Given, $E=2\text{V};r=1\Omega ;R=6\Omega$

Current through the external resistance is,

$I=\frac{E}{R+\frac{r}{n}}=\frac{2}{6+\frac{1}{4}}=\frac{2}{6.25}$

$\Rightarrow I=0.32\text{A}$

<!--td {border: 1px solid #ccc;}br {mso-data-placement:same-cell;}--> Hence, $\left(D\right)$ is the correct answer.