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Question

# Four changed particles, each having a charge q, are placed at the four vertices of a regular pentagon. The sides of the Pentagon have equal length 'a'. The electric field at the centre of the Pentagon is :

A
q4πε0a
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B
2q4πε0a2
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C
q4πε0a2
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D
None of these
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Solution

## The correct option is C q4πε0a2Suppose if charge ′q′ is placed at E as well as →E(atpointO)=0 because of symmetry.→E(center because of charge,A,B,C,D)=→E(center because of charge E alone)\$→E(at center due to charge q)=q4πϵ0a2∴ Electric field at O will be same i.e. q4πϵ0a2 along OE due to given system of charge.

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