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Four charge particles He++, proton, deutron and Li++ enters a region of uniform magnetic field and moves in a circular path of different radius. List I gives above four particles while list II gives magnitude of some quantity.

List IList III - He++P) 1II - ProtonQ) 2III - deutronR) 12IV) Li++S) 2T) 72U) 12
If kinetic energy of all four particles is same than correct match for radius of four particles in units of radius of proton is

A
IP,IIP,IIIS,IVT
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B
IQ,IIP,IIIS,IVT
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C
IS,IIP,IIIS,IVT
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D
IR,IIP,IIIS,IVT
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Solution

The correct option is A IP,IIP,IIIS,IVT
IP,IIP,IIIS,IVT
Since R=mvqB=2mEqB = is energy
RP=2MEeB=R0(let)
RHe++=2×4mE2eB=R0
Rd=2×2mEeB=2 R0
RLi++=2×7mE2eB=72R0

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