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Question

Four charges each of +103×109C are placed at four corners of a square of side 8 cm. The potential at the intersection of the diagonals is 
  1. 1502 volt
  2. 15002 volt
  3. 900 volt
  4. 9002 volt


Solution

The correct option is B 15002 volt
Given Q=103×109C and a=8 cm=8×102m

Potential due to a point charge V=14πϵ0.QR




Potential at the centre O due to four charges 
V=4×14πϵ0.Qa/2

So V=4×9×109×103×1098×1022=15002 volt

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