Four charges $+ Q, - Q, + Q$ and $- Q$ are situated at the corners of a square; in a sequence then at the centre of the square:

E = 0, V = 0

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E = 0, V \neq 0

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E \neq 0, V = 0

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E \neq 0, V \neq 0

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Solution

The correct option is C $E \neq 0, V = 0$
Four charges $+ Q$ , $- Q$ , $+ Q$ , $- Q$ .
In this context, $E \neq 0$ but $V = 0$ because. $E$ is not cancel out to each other but $V$ is cancel out each other.

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