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Standard XII

Physics

Charging by Friction

Four charges ...

Question

Four charges $+ Q, - Q, + Q, - Q$ are placed at the corners of a square taken order. At the centre of the square :

E = 0,

V = 0

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E = 0

V \neq 0

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E \neq 0

V = 0

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E \neq 0

V \neq 0

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Solution

The correct option is B $E = 0,$ $V = 0$

Four charges $+ Q, - Q, + Q, - Q$ .
In this context $E = 0$ as well $V = 0$
because, at the centre there is needed all cancel out because $θ$ . If $E = 0$ and $V = 0$

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Four charges +Q,−Q,+Q,−Q are placed at the corners of a square taken order. At the centre of the square :

The correct option is B E=0, V=0Four charges +Q,−Q,+Q,−Q.In this context E=0 as well V=0because, at the centre there is needed all cancel out because θ. If E=0 and V=0

Four charges $+ Q, - Q, + Q, - Q$ are placed at the corners of a square taken order. At the centre of the square :

The correct option is B $E = 0,$ $V = 0$

Four charges $+ Q, - Q, + Q, - Q$ .
In this context $E = 0$ as well $V = 0$
because, at the centre there is needed all cancel out because $θ$ . If $E = 0$ and $V = 0$