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Question

Four cubes of ice at -10 oC weighing one gram each is taken out from the refrigerator and are put in 150 grams of water at 20 oC. What is the final temperature of water when thermal equilibrium is attained? Assume that no heat is lost to the outside and water equivalent of container is 46 g. (Specific heat capacity of water = 1 cal/g-oC, Specific heat capacity of ice = 0.5 cal/g-oC, Latent heat of fusion of ice = 80 cal/g-oC)


A
0 oC
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B
-10 oC
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C
17.9 oC
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D
None
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Solution

The correct option is C 17.9 oC
Heat gained by ice = Heat lost by water + Heat lost by container
Initial temperature of container = 20o C
4×12×10 + 4×80 + 4×1×(T0) = 196×1×(20T)20+320+4T=196×20196T200T=196×20340T=3580200=17.9o C

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