Volume of each cube = 125 cm3
So, Edge of each cube = 5 cm
For new cuboid formed, l = 5+5+5+5 = 20 cm
b = 5 cm
h = 5 cm
Therefore, surface area of the resulting cuboid = 2 (lb + bh + lh)
= 2 (20 X 5 + 5 X 5 + 20 X 5) cm2
= 450 cm2
And volume of cuboid=l x b x h = 20 x 5 x 5 = 500cm3
Regards