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Question

Four curves A, B, C and D are drawn for given mass of gas. The curves which represent adiabatic and isothermal expansion are respectively
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A
A and B
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B
C and D
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C
B and A
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D
D and C
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Solution

The correct option is A A and B
For an isothermal process PV=constant

Differentiating we get
PdV+VdP=0
or
dPdV=PV
or
tanθ=dPdV=PV-----------------------(i)

For a adiabatic process, we have
PVγ=constant
Differentiating we get
dPVγ+PγVγ1=0
or
dPdV=γPVγ1Vγ=γ(PV)
Thus slope is tanθ=dPdV=γPV................(ii)

Thus, slope of adiabatic process is more than the slope of isothermal process.
Also as P1V. Thus. we get the answer as A.

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