Four die are thrown simultaneously. The probability that $4$ and $3$ appear on two of the die given that $5$ and $6$ have appeared on other two die is?

1 / 6

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1 / 36

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12 / 151

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None of these

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Solution

The correct option is D None of these
5 and 6 appeared on other two and its definite with probability=1
4 and 3 appears on remaining two like 4,3 or 3,4=21/61/6=1/18

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Four die are thrown simultaneously. The probability that 4 and 3 appear on two of the die given that 5 and 6 have appeared on other two die is?

The correct option is D None of these5 and 6 appeared on other two and its definite with probability=14 and 3 appears on remaining two like 4,3 or 3,4=2*1/6*1/6=1/18

Four die are thrown simultaneously. The probability that $4$ and $3$ appear on two of the die given that $5$ and $6$ have appeared on other two die is?

The correct option is D None of these
5 and 6 appeared on other two and its definite with probability=1
4 and 3 appears on remaining two like 4,3 or 3,4=21/61/6=1/18