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Question

Four digit numbers are formed using the digits 1,2,3,4 (repetitions among the digits allowed). Find the number of such four digit numbers divisible by 11

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Solution

Let abcd be the number.
If a=b then c=d.

There are 4×4=16 ways ---(1)

Which can occur. (Four options for a and four options for b.


If a=b±1 then c=d±1.

And there are 2×3×3=18 ways.---(2)

this can occur. (Two choices whether a>b or b>a and three choices from 1,2,3,4 that are one apart.
If a=b±2 then c=d±2

and there are 2×2×2=8 ways. ---(3)
And if a=b±4 then

either a=1;b=4;c=4;d=1 (or)

a=4;b=1;c=1;d=4.

Which are 2 ways. ---(4)

From (1), (2), (3) and (4)

Required number of ways =16+18+8+2=44 ways.


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