Four digit numbers of the form N = abcd are to be formed which satisfy the conditions (i) 4000 < N < 6000 (ii) 3≤b<c≤6 (iii) N is a multiple of 5 then which of the following is/are true
A
number of such numbers is 24
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B
Number of such numbers is 48
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C
number of such even numbers is 12
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D
number of such even numbers in 24
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Solution
The correct options are A number of such numbers is 24 C number of such even numbers is 12 N =a b c d ‘a’ can be assigned in 2 ways ( 4 or 5) b c can be assigned in 6 ways (34, 35, 36, 45, 46, 56) d can be assigned in 2 ways(0 or 5) ∴ total no. Of number = 2×6×2=24 Half of them are even