Question

Four distinct numbers are selected from first 100 natural numbers. How many numbers are there which are divisible by both 3 and 5?

• A. 6
• B. 7
• C. 4
• D. 2

Answer 1

The correct option is D 2

Option(d)

A number divisible by both 3 as well as 5 has to be divisible by 15. In the first 100 natural numbers, there are 6 such numbers-> 15, 30, 45, 60, 75, 90

Favourable number of ways = ${}^6{C}_4$