Question

Four electrical charges are arranged on the corners of a $10cm$ square as shown What would be the direction of the resulting electric field at the center point P?

• A. $\to$
• B. $\leftarrow$
• C. $\uparrow$
• D. $\downarrow$

Answer 1

The correct option is C $\uparrow$

Electric field at P due to a positive charge 0$Q$ at corner=$F=\frac{Q}{4\pi {ϵ}_o{r}^2}$ where $r$= distance between corner and P

The direction of field and the resultant field are shown in figure.

Hence, the resultant field at $P=\sqrt{2}F$ bisecting the two F vectors shown in 2nd figure .

Hence, field is in vertically upward direction $(\uparrow )$.

Answer-(C)