Four elements A, B, C and D have the following electron arrangements in their atoms:
$\begin{matrix} A & 2, 8, 6 B & 2, 8, 8 C & 2, 8, 8, 1 D & 2, 7 \end{matrix}$
(a) What type of bond is formed when element C combines with element D?
(b) Which element is an inert gas?
(c) What will be the formula of the compound between A and C?

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Solution

(a) When element C combines with element D, an ionic bond is formed between them by transfer of one electron from element C atom to element D atom.

(b) Element B is an inert gas because it has 8 electrons in its valence shell; i.e, it contains a completely filled valence shell.

(c) The formula of the compound will be $A C_{2}$ . Because element A needs two electrons to complete its octet, two atoms of element C donate two electrons to element A and get stabilised.

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Four elements A, B, C and D have the following electron arrangements in their atoms: A2,8,6B2,8,8C2,8,8,1D2,7 (a) What type of bond is formed when element C combines with element D? (b) Which element is an inert gas? (c) What will be the formula of the compound between A and C?