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Ionization Enthalpy

Four elements...

Question

Four elements P, Q, R and S have ground state electronic configuration as:
$P \to 1 s^{2} 2 s^{2} 2 p^{6} 3 s^{2} 3 p^{3} Q \to 1 s^{2} 2 s^{2} 2 p^{6} 3 s^{2} 3 p^{1} R \to 1 s^{2} 2 s^{2} 2 p^{6} 3 s^{2} 3 p^{6} 3 d^{10} 4 s^{2} 4 p^{3} S \to 1 s^{2} 2 s^{2} 2 p^{6} 3 s^{2} 3 p^{6} 3 d^{10} 4 s^{2} 4 p^{1}$
Select the correct statement (s) among the following:

A

Size of

R

< size of

S

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B

Size of

P

< size of

Q

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C

Size of

P

< size of

R

(appreciable difference)

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D

Size of

Q

< size of

S

(appreciable difference)

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Solution

The correct option is C Size of $P$ < size of $R$ (appreciable difference)
P - Phosphorus (P), R - Arsenic (As)
Q - Aluminium (Al), S- Gallium (Ga)
As we know, according to the general trend, on going left to right in a period of the periodic table, size decreases and on moving top to bottom in a group, size increases.
But due to the poor screening effect of $3 d$ electrons, the size of $G a$ is less than that of $A l$
(A) $P < A l$
(B) $A s < G a$
(C) $P < A s$
(D) $A l > G a$

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Q. Four elements P, Q, R and S have ground state electronic configuration as:

P \to 1 s^{2} 2 s^{2} 2 p^{6} 3 s^{2} 3 p^{3} Q \to 1 s^{2} 2 s^{2} 2 p^{6} 3 s^{2} 3 p^{1} R \to 1 s^{2} 2 s^{2} 2 p^{6} 3 s^{2} 3 p^{6} 3 d^{10} 4 s^{2} 4 p^{3} S \to 1 s^{2} 2 s^{2} 2 p^{6} 3 s^{2} 3 p^{6} 3 d^{10} 4 s^{2} 4 p^{1}

Select the correct statement (s) among the following:

Q. which of the following option doesnot represent ground state electronic configuration of an atom ? 1. 1s2 2s2 2p6 3s2 3p6 3d8 4s2 2. 1s2 2s2 2p6 3s2 3p6 3d9 4s2 3. 1s2 2s2 2p6 3s2 3p6 3d10 4

Q. If
A = 1s², 2s², 2p¹
B = 1s², 2s², 2p⁶, 3s², 3p¹
C = 1s², 2s², 2p⁶, 3s², 3p³
D = 1s², 2s², 2p⁶, 3s², 3p⁵
E = 1s², 2s², 2p⁶, 3s², 3p⁶ 4s²
F = 1s², 2s², 2p⁶, 3s² 4s², 3d¹

Q. Subshell electronic configuration of two elements are given. To which block, period and group does each belong

(a) 1 s^{2} 2 s^{2} 2 p^{6} 3 s^{2} (b) 1 s^{2} 2 s^{2} 2 p^{6} 3 s^{2} 3 p^{6} 3 d^{3} 4 s^{2}

Q. 35. What is the correct way of writing electronic configuration? E.g. for Zn (which is correct between the two) 1)1s2 2s2 2p6 3s2 3p6 3d10 4s2 2) 1s2 2s2. 2p6. 3s2. 3p6. 4s2. 3d10 & Therefore, how would we find kernel electrons?Will we exclude 4s2 subshell or 3d10 subshell while writing kernels?

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