Question

Four employees enter into a conference hall where there are 8 seats. The number of ways they can choose their seat is .

Answer 1

Given their are $8$ seats in conference room.
First employee can take one of the $8$ seats.
Second can take one of the remaining $7$ seats.
Third can take from $6$ remaining seats.
And fourth one can take among any of the $5$ seats.

Using counting principle, the number of ways they can choose their seats is $=8\times 7\times 6\times 5=1680.$